Area of a Regular Octagon side 5 ft Calculator
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Area of a Regular Octagon side 5 ft is 120.7106781 ft²
Area of a Regular Octagon side 5 ft is 120.7106781 ft²
Area of a Regular Octagon side 5 ft in other units
| Value | unit |
|---|---|
| 0.0367926 | km² |
| 0.0228619 | mi² |
| 36.7926147 | m² |
| 120.7106781 | ft² |
| 1448.5281372 | in² |
| 40.2368927 | yd² |
| 3679.2614685 | cm² |
| 36792.6146849 | mm² |
Steps:
Given that Side, a = 5 ft
We know that, Area = 2 (1 + √2) * a²
Put the value of side in area Formula.
A = 2 (1 + √2) * 5²
Simplify the above equation
A = 120.7106781 ft²
∴ Area of a Regular Octagon side 5 ft is 120.7106781 ft²