Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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Regular Octagon Side


Area of a Regular Octagon side 41 ft is 8116.5859967 ft²

Area of a Regular Octagon side 41 ft is 8116.5859967 ft²


    Area of a Regular Octagon side 41 ft in other units

Value unit
2.4739354 km²
1.537236 mi²
2473.9354118
8116.5859967 ft²
97399.0319604 in²
2705.5286656 yd²
247393.5411794 cm²
2473935.4117942 mm²

Steps:

Given that Side, a = 41 ft

We know that, Area = 2 (1 + √2) * a²

Put the value of side in area Formula.

A = 2 (1 + √2) * 41²

Simplify the above equation

A = 8116.5859967 ft²

∴ Area of a Regular Octagon side 41 ft is 8116.5859967 ft²