Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 72 inches by width 96 in by height 32 in is 73728.0 inches3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 72 inches by width 96 in by height 32 in is 73728.0 inches3.


    Volume of Cone 72 in by 96 in by 32 in in other units

Value unit
1.8726912 km3
1.1636393 mi3
1872.6912 m3
6144.0 ft3
73728.0 in3
2048.0 yd3
187269.12 cm3
1872691.2 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 72 in , the width w = 96 in , and the height h = 32 in into the formula

$1\above 1pt3$ * (72 in * 96 in * 32 in)

Multiply 72 in and 96 in

$1\above 1pt3$ * 6912.0 in2 * 32 in

Multiply 6912.0 in2 and 32 in

Divide 221184.0 in by number 3

Volume = 73728.0 in3

∴ Volume of a Pyramid length 72 in , width 96 in and height 32 in is 73728.0 in2