Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 71 inches by width 96 in by height 33 in is 74976.0 inches3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 71 inches by width 96 in by height 33 in is 74976.0 inches3.


    Volume of Cone 71 in by 96 in by 33 in in other units

Value unit
1.9043904 km3
1.1833363 mi3
1904.3904 m3
6248.0 ft3
74976.0 in3
2082.6666667 yd3
190439.04 cm3
1904390.4 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 71 in , the width w = 96 in , and the height h = 33 in into the formula

$1\above 1pt3$ * (71 in * 96 in * 33 in)

Multiply 71 in and 96 in

$1\above 1pt3$ * 6816.0 in2 * 33 in

Multiply 6816.0 in2 and 33 in

Divide 224928.0 in by number 3

Volume = 74976.0 in3

∴ Volume of a Pyramid length 71 in , width 96 in and height 33 in is 74976.0 in2