Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 45 foot by width 98 ft by height 67 ft is 98490.0 foot3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 45 foot by width 98 ft by height 67 ft is 98490.0 foot3.


    Volume of Cone 45 ft by 98 ft by 67 ft in other units

Value unit
30.019752 km3
18.6534555 mi3
30019.752 m3
98490.0 ft3
1181880.0 in3
32830.0 yd3
3001975.2 cm3
30019752.0 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 45 ft , the width w = 98 ft , and the height h = 67 ft into the formula

$1\above 1pt3$ * (45 ft * 98 ft * 67 ft)

Multiply 45 ft and 98 ft

$1\above 1pt3$ * 4410.0 ft2 * 67 ft

Multiply 4410.0 ft2 and 67 ft

Divide 295470.0 ft by number 3

Volume = 98490.0 ft3

∴ Volume of a Pyramid length 45 ft , width 98 ft and height 67 ft is 98490.0 ft2