Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 44 inches by width 56 in by height 27 in is 22176.0 inches3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 44 inches by width 56 in by height 27 in is 22176.0 inches3.


    Volume of Cone 44 in by 56 in by 27 in in other units

Value unit
0.5632704 km3
0.3500009 mi3
563.2704 m3
1848.0 ft3
22176.0 in3
616.0 yd3
56327.04 cm3
563270.4 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 44 in , the width w = 56 in , and the height h = 27 in into the formula

$1\above 1pt3$ * (44 in * 56 in * 27 in)

Multiply 44 in and 56 in

$1\above 1pt3$ * 2464.0 in2 * 27 in

Multiply 2464.0 in2 and 27 in

Divide 66528.0 in by number 3

Volume = 22176.0 in3

∴ Volume of a Pyramid length 44 in , width 56 in and height 27 in is 22176.0 in2