Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 41 foot by width 98 ft by height 67 ft is 89735.3333333 foot3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 41 foot by width 98 ft by height 67 ft is 89735.3333333 foot3.


    Volume of Cone 41 ft by 98 ft by 67 ft in other units

Value unit
27.3513296 km3
16.9953705 mi3
27351.3296 m3
89735.3333333 ft3
1076823.9999996 in3
29911.7777778 yd3
2735132.959999 cm3
27351329.5999898 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 41 ft , the width w = 98 ft , and the height h = 67 ft into the formula

$1\above 1pt3$ * (41 ft * 98 ft * 67 ft)

Multiply 41 ft and 98 ft

$1\above 1pt3$ * 4018.0 ft2 * 67 ft

Multiply 4018.0 ft2 and 67 ft

Divide 269206.0 ft by number 3

Volume = 89735.3333333 ft3

∴ Volume of a Pyramid length 41 ft , width 98 ft and height 67 ft is 89735.3333333 ft2