Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 40 foot by width 98 ft by height 69 ft is 90160.0 foot3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 40 foot by width 98 ft by height 69 ft is 90160.0 foot3.


    Volume of Cone 40 ft by 98 ft by 69 ft in other units

Value unit
27.480768 km3
17.0758 mi3
27480.768 m3
90160.0 ft3
1081920.0 in3
30053.3333333 yd3
2748076.8 cm3
27480768.0 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 40 ft , the width w = 98 ft , and the height h = 69 ft into the formula

$1\above 1pt3$ * (40 ft * 98 ft * 69 ft)

Multiply 40 ft and 98 ft

$1\above 1pt3$ * 3920.0 ft2 * 69 ft

Multiply 3920.0 ft2 and 69 ft

Divide 270480.0 ft by number 3

Volume = 90160.0 ft3

∴ Volume of a Pyramid length 40 ft , width 98 ft and height 69 ft is 90160.0 ft2