Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 40 foot by width 103 ft by height 67 ft is 92013.3333333 foot3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 40 foot by width 103 ft by height 67 ft is 92013.3333333 foot3.


    Volume of Cone 40 ft by 103 ft by 67 ft in other units

Value unit
28.045664 km3
17.426811 mi3
28045.664 m3
92013.3333333 ft3
1104159.9999996 in3
30671.1111111 yd3
2804566.399999 cm3
28045663.9999898 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 40 ft , the width w = 103 ft , and the height h = 67 ft into the formula

$1\above 1pt3$ * (40 ft * 103 ft * 67 ft)

Multiply 40 ft and 103 ft

$1\above 1pt3$ * 4120.0 ft2 * 67 ft

Multiply 4120.0 ft2 and 67 ft

Divide 276040.0 ft by number 3

Volume = 92013.3333333 ft3

∴ Volume of a Pyramid length 40 ft , width 103 ft and height 67 ft is 92013.3333333 ft2