Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Volume of a Pyramid length 13 inches by width 39 in by height 41 in is 6929.0 inches3

The Volume of a Pyramid is equal to the 1/3 times length(1) times the width(w) times the height(h). If the Pyramid has a length 13 inches by width 39 in by height 41 in is 6929.0 inches3.


    Volume of Cone 13 in by 39 in by 41 in in other units

Value unit
0.1759966 km3
0.1093595 mi3
175.9966 m3
577.4166667 ft3
6929.0 in3
192.4722222 yd3
17599.66 cm3
175996.6 mm3

Steps:

The volume of a pyramid is equal to $1\above 1pt3$ *length * width * height

Substitute the values of the length l = 13 in , the width w = 39 in , and the height h = 41 in into the formula

$1\above 1pt3$ * (13 in * 39 in * 41 in)

Multiply 13 in and 39 in

$1\above 1pt3$ * 507.0 in2 * 41 in

Multiply 507.0 in2 and 41 in

Divide 20787.0 in by number 3

Volume = 6929.0 in3

∴ Volume of a Pyramid length 13 in , width 39 in and height 41 in is 6929.0 in2