Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of bottom radius(r)

Enter the Value of height(h)


Surface Area of Cylinder Base Radius 95 inches by height 21 inches is 69205.6 inches2

The Surface Area of a Cylinder is equal to the sum of the areas of the bases each having an area of π ⋅ r2 , plus the area of the side. The area of the side is equal to the area of a rectangle with length 2 π r (the circumference of the base) times the height. Surface Area of Cylinder Base Radius 95 inches by height 21 inches is69205.6 inches2.


    Surface Area of a Cylinder 95 in by 21 in in other units

Value unit
1.7578222 km2
1.0922628 mi2
1757.82224 m2
5767.1333333 ft2
69205.6 in2
1922.3777778 yd2
175782.224 cm2
1757822.24 mm2

Steps:

Given that Base radius(r) = 95 in and height(h) = 21 in

The Surface Area of Cylinder = 2π .(Radius)2 + 2π .(Radius) . (Height)

Substitute the values of the radius r = 95 in and height h = 21 in into the formula. Pi (π) is approximately equal to 3.14 .

2 . (π) . (952) in2 + 2 .(π) . (95) in . (21.0) in

Raise 95.0 in to the power of 2.

2 .(π) . (9025.0) in2 + 2 . (π) . (95.0) in . (21.0) in

Multiply 9025.0 in2 by 2

18050.0 in2 . π + 2 .(π) . 95.0 in . 21.0 in

Multiply 95.0 in and 21.0 in

18050.0 in . π + 1995.0 in2 . π . 2

Multiply 1995.0 in2 and 2

18050.0 in2 . π + 3990.0 in2 . π

Add 18050.0 . π in2 and 3990.0 . π in2

The result can be shown in multiple forms.

Exact Form

22040.0 . π in2

∴ Surface Area of Cylinder 95.0 in by 21.0 in is 22040.0 . π in2

Decimal Form

69205.6 in2

∴ Surface Area of Cylinder 95.0 in by 21.0 in is 69205.6 in2