Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of base radius(r)

Enter the Value of height(h)


If the cone Radius 41 meters by height 55 meters is 14109.9415334 meters2.


The surface area of a cone is equal to the area of the base plus the area of the cone. If the cone Radius 41 meters by height 55 meters is 14109.9415334 meters2.


    Surface Area of a Cone 41 m by 55 m in other units

Value unit
14.1099415 km2
8.767533 mi2
14109.9415334 m2
46292.4590991 ft2
555509.509189 in2
15430.8196997 yd2
1410994.15334 cm2
14109941.5334 mm2

Steps:

Given that Base radius(r) = 41 m and height(h) = 55 m

Surface Area of a Cone = $(π⋅(Radius))$⋅($(Radius)$ + $\sqrt{(Radius)^2+(Height)^2}$)

Substitute the values of the radius r = 41 m and height h = 55 m into the formula. Pi (π) is approximately equal to 3.14 .

$(π⋅(41))$⋅ $(41$ + $\sqrt{(41)^2 + (55)^2})$

Move 41 to the left of π.

$(41π)$⋅$ (41$ + $\sqrt{(41)^2 + (55)^2}$

Simplify each term

Raise 41 m to the power of 2 and 55 to the power of 2

$(41π)$⋅$ (41$ + $\sqrt{(1681.0) + (3025.0)}$ m

Add 1681.0 m and 3025.0 m

$(41π)$ m⋅$ (41$ + $\sqrt{(4706.0)}$ m

Multipy 41π m and 41 m

1681.0π m + (41π . $\sqrt4706.0$)m

Put the value of $\sqrt4706.0$ = 68.6002915 in formula

1681.0π m + (41π . 68.6002915) m

Mulitply the 41π and 68.6002915

1681.0π m + (2812.6119533π)

Add 1681.0π m and 2812.6119533π m

The result can be shown in multiple forms

Exact Form

Area = 4493.6119533π m

∴ Surface Area of Cone 41 m by 55 m is 4493.6119533π m2

Decimal Form

14109.9415334 m2

∴ Surface Area of Cylinder 41 m by 55 m is 14109.9415334 m2