Surface area of a Pyramid 98 inches by 42 inches by 41 inches Calculator

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 98 inches by width 42 inches by height 41 inches is 11313.789098 inches².

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =98 , the width w =42 , and the height h =41 into the formula for surface area of a pyramid

A=($98 \cdot42+98$$\sqrt{(\frac{42}{2})^2+(41)^2}$$+42$$\sqrt{(\frac{98}{2})^2+(41)^2}$) in

Simplify each term.

Multiply 98 in by 42 in

A = $4116.0 + 98$$\sqrt{(\frac{42}{2})^2+(41)^2}$$+42$$\sqrt{(\frac{98}{2})^2+(41)^2}$

Square root of $\sqrt{(\frac{42}{2})^2+(41)^2}$ is 46.0651712

Put The values in Area Formula:

A= $4116.0 + 98 \cdot 46.0651712 + 42$$\sqrt{(\frac{98}{2})^2 + (41)^2}$

Square Root of $\sqrt{(\frac{98}{2})^2+(41)^2}$ is 63.8905314

Put The values in Area Formula:

A= 4116.0 + 98 x 46.0651712 + 42 x 63.8905314

Multiply 98 and 46.0651712

A= 4116.0 + 4514.3867801 + 42 x 63.8905314

Multiply 42 and 63.8905314

A= 4116.0 + 4514.3867801 + 2683.402318

Add 4116.0 and 4514.3867801

A=8630.3867801 + 2683.402318

A= 11313.789098 in²

∴ The Surface Area of Pyramid length 98 in , width 42 in and height 41 in is 11313.789098 in²