Surface area of a Pyramid 73 inches by 96 inches by 32 inches Calculator
The Surface Area of Pyramid 73 inches by width 96 inches by height 32 inches is 15879.2409711 inches2.
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 73 inches by width 96 inches by height 32 inches is 15879.2409711 inches2.
Surface Area of a Pyramid 73 in by 96 in by 32 in in other units
Value | unit |
---|---|
0.4033327 | km2 |
0.25062 | mi2 |
403.3327207 | m2 |
1323.2700809 | ft2 |
15879.2409711 | in2 |
441.090027 | yd2 |
40333.2720666 | cm2 |
403332.7206659 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =73 , the width w =96 , and the height h =32 into the formula for surface area of a pyramid
A=($73 \cdot96+73$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{73}{2})^2+(32)^2}$) in
Simplify each term.
Multiply 73 in by 96 in
A = $7008.0 + 73$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{73}{2})^2+(32)^2}$
Square root of $\sqrt{(\frac{96}{2})^2+(32)^2}$ is 57.6888204
Put The values in Area Formula:
A= $7008.0 + 73 \cdot 57.6888204 + 96$$\sqrt{(\frac{73}{2})^2 + (32)^2}$
Square Root of $\sqrt{(\frac{73}{2})^2+(32)^2}$ is 48.5412196
Put The values in Area Formula:
A= 7008.0 + 73 x 57.6888204 + 96 x 48.5412196
Multiply 73 and 57.6888204
A= 7008.0 + 4211.2838897 + 96 x 48.5412196
Multiply 96 and 48.5412196
A= 7008.0 + 4211.2838897 + 4659.9570813
Add 7008.0 and 4211.2838897
A=11219.2838897 + 4659.9570813
A= 15879.2409711 in2
∴ The Surface Area of Pyramid length 73 in , width 96 in and height 32 in is 15879.2409711 in2