Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 72 inches by width 96 inches by height 32 inches is 15689.5673876 inches2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 72 inches by width 96 inches by height 32 inches is 15689.5673876 inches2.


    Surface Area of a Pyramid 72 in by 96 in by 32 in in other units

Value unit
0.398515 km2
0.2476264 mi2
398.5150116 m2
1307.463949 ft2
15689.5673876 in2
435.8213163 yd2
39851.5011645 cm2
398515.011645 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =72 , the width w =96 , and the height h =32 into the formula for surface area of a pyramid

A=($72 \cdot96+72$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{72}{2})^2+(32)^2}$) in

Simplify each term.

Multiply 72 in by 96 in

A = $6912.0 + 72$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{72}{2})^2+(32)^2}$

Square root of $\sqrt{(\frac{96}{2})^2+(32)^2}$ is 57.6888204

Put The values in Area Formula:

A= $6912.0 + 72 \cdot 57.6888204 + 96$$\sqrt{(\frac{72}{2})^2 + (32)^2}$

Square Root of $\sqrt{(\frac{72}{2})^2+(32)^2}$ is 48.1663783

Put The values in Area Formula:

A= 6912.0 + 72 x 57.6888204 + 96 x 48.1663783

Multiply 72 and 57.6888204

A= 6912.0 + 4153.5950693 + 96 x 48.1663783

Multiply 96 and 48.1663783

A= 6912.0 + 4153.5950693 + 4623.9723183

Add 6912.0 and 4153.5950693

A=11065.5950693 + 4623.9723183

A= 15689.5673876 in2

∴ The Surface Area of Pyramid length 72 in , width 96 in and height 32 in is 15689.5673876 in2