Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 71 inches by width 96 inches by height 35 inches is 15819.6015264 inches2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 71 inches by width 96 inches by height 35 inches is 15819.6015264 inches2.


    Surface Area of a Pyramid 71 in by 96 in by 35 in in other units

Value unit
0.4018179 km2
0.2496787 mi2
401.8178788 m2
1318.3001272 ft2
15819.6015264 in2
439.4333757 yd2
40181.7878771 cm2
401817.8787706 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =71 , the width w =96 , and the height h =35 into the formula for surface area of a pyramid

A=($71 \cdot96+71$$\sqrt{(\frac{96}{2})^2+(35)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(35)^2}$) in

Simplify each term.

Multiply 71 in by 96 in

A = $6816.0 + 71$$\sqrt{(\frac{96}{2})^2+(35)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(35)^2}$

Square root of $\sqrt{(\frac{96}{2})^2+(35)^2}$ is 59.405387

Put The values in Area Formula:

A= $6816.0 + 71 \cdot 59.405387 + 96$$\sqrt{(\frac{71}{2})^2 + (35)^2}$

Square Root of $\sqrt{(\frac{71}{2})^2+(35)^2}$ is 49.8522818

Put The values in Area Formula:

A= 6816.0 + 71 x 59.405387 + 96 x 49.8522818

Multiply 71 and 59.405387

A= 6816.0 + 4217.7824742 + 96 x 49.8522818

Multiply 96 and 49.8522818

A= 6816.0 + 4217.7824742 + 4785.8190522

Add 6816.0 and 4217.7824742

A=11033.7824742 + 4785.8190522

A= 15819.6015264 in2

∴ The Surface Area of Pyramid length 71 in , width 96 in and height 35 in is 15819.6015264 in2