Surface area of a Pyramid 71 inches by 96 inches by 35 inches Calculator
The Surface Area of Pyramid 71 inches by width 96 inches by height 35 inches is 15819.6015264 inches2.
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 71 inches by width 96 inches by height 35 inches is 15819.6015264 inches2.
Surface Area of a Pyramid 71 in by 96 in by 35 in in other units
Value | unit |
---|---|
0.4018179 | km2 |
0.2496787 | mi2 |
401.8178788 | m2 |
1318.3001272 | ft2 |
15819.6015264 | in2 |
439.4333757 | yd2 |
40181.7878771 | cm2 |
401817.8787706 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =71 , the width w =96 , and the height h =35 into the formula for surface area of a pyramid
A=($71 \cdot96+71$$\sqrt{(\frac{96}{2})^2+(35)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(35)^2}$) in
Simplify each term.
Multiply 71 in by 96 in
A = $6816.0 + 71$$\sqrt{(\frac{96}{2})^2+(35)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(35)^2}$
Square root of $\sqrt{(\frac{96}{2})^2+(35)^2}$ is 59.405387
Put The values in Area Formula:
A= $6816.0 + 71 \cdot 59.405387 + 96$$\sqrt{(\frac{71}{2})^2 + (35)^2}$
Square Root of $\sqrt{(\frac{71}{2})^2+(35)^2}$ is 49.8522818
Put The values in Area Formula:
A= 6816.0 + 71 x 59.405387 + 96 x 49.8522818
Multiply 71 and 59.405387
A= 6816.0 + 4217.7824742 + 96 x 49.8522818
Multiply 96 and 49.8522818
A= 6816.0 + 4217.7824742 + 4785.8190522
Add 6816.0 and 4217.7824742
A=11033.7824742 + 4785.8190522
A= 15819.6015264 in2
∴ The Surface Area of Pyramid length 71 in , width 96 in and height 35 in is 15819.6015264 in2