Surface area of a Pyramid 71 inches by 96 inches by 32 inches Calculator

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The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 71 inches by width 96 inches by height 32 inches is 15500.1137421 inches2.


    Surface Area of a Pyramid 71 in by 96 in by 32 in in other units

Value unit
0.3937029 km2
0.2446362 mi2
393.702889 m2
1291.6761452 ft2
15500.1137421 in2
430.5587151 yd2
39370.2889049 cm2
393702.8890493 mm2


Surface area of a Pyramid 71 inches by 96 inches by 32 inches

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =71 , the width w =96 , and the height h =32 into the formula for surface area of a pyramid

A=($71 \cdot96+71$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(32)^2}$) in

Simplify each term.

Multiply 71 in by 96 in

A = $6816.0 + 71$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(32)^2}$

Square root of $\sqrt{(\frac{96}{2})^2+(32)^2}$ is 57.6888204

Put The values in Area Formula:

A= $6816.0 + 71 \cdot 57.6888204 + 96$$\sqrt{(\frac{71}{2})^2 + (32)^2}$

Square Root of $\sqrt{(\frac{71}{2})^2+(32)^2}$ is 47.7938281

Put The values in Area Formula:

A= 6816.0 + 71 x 57.6888204 + 96 x 47.7938281

Multiply 71 and 57.6888204

A= 6816.0 + 4095.9062489 + 96 x 47.7938281

Multiply 96 and 47.7938281

A= 6816.0 + 4095.9062489 + 4588.2074931

Add 6816.0 and 4095.9062489

A=10911.9062489 + 4588.2074931

A= 15500.1137421 in2

∴ The Surface Area of Pyramid length 71 in , width 96 in and height 32 in is 15500.1137421 in2

Surface Area & Volume of The Pyramid Calculations

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