# Surface area of a Pyramid 71 inches by 96 inches by 32 inches Calculator

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The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 71 inches by width 96 inches by height 32 inches is 15500.1137421 inches2.

Surface Area of a Pyramid 71 in by 96 in by 32 in in other units

Value unit
0.3937029 km2
0.2446362 mi2
393.702889 m2
1291.6761452 ft2
15500.1137421 in2
430.5587151 yd2
39370.2889049 cm2
393702.8890493 mm2

## Surface area of a Pyramid 71 inches by 96 inches by 32 inches

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2} Substitute the values of the length l =71 , the width w =96 , and the height h =32 into the formula for surface area of a pyramid A=(71 \cdot96+71$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(32)^2}$) in

Simplify each term.

Multiply 71 in by 96 in

A = $6816.0 + 71$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(32)^2} Square root of \sqrt{(\frac{96}{2})^2+(32)^2} is 57.6888204 Put The values in Area Formula: A= 6816.0 + 71 \cdot 57.6888204 + 96$$\sqrt{(\frac{71}{2})^2 + (32)^2}$

Square Root of $\sqrt{(\frac{71}{2})^2+(32)^2}$ is 47.7938281

Put The values in Area Formula:

A= 6816.0 + 71 x 57.6888204 + 96 x 47.7938281

Multiply 71 and 57.6888204

A= 6816.0 + 4095.9062489 + 96 x 47.7938281

Multiply 96 and 47.7938281

A= 6816.0 + 4095.9062489 + 4588.2074931