Surface area of a Pyramid 71 inches by 96 inches by 32 inches Calculator
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 71 inches by width 96 inches by height 32 inches is 15500.1137421 inches2.
Surface Area of a Pyramid 71 in by 96 in by 32 in in other units
| Value | unit |
|---|---|
| 0.3937029 | km2 |
| 0.2446362 | mi2 |
| 393.702889 | m2 |
| 1291.6761452 | ft2 |
| 15500.1137421 | in2 |
| 430.5587151 | yd2 |
| 39370.2889049 | cm2 |
| 393702.8890493 | mm2 |
Surface area of a Pyramid 71 inches by 96 inches by 32 inches
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =71 , the width w =96 , and the height h =32 into the formula for surface area of a pyramid
A=($71 \cdot96+71$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(32)^2}$) in
Simplify each term.
Multiply 71 in by 96 in
A = $6816.0 + 71$$\sqrt{(\frac{96}{2})^2+(32)^2}$$+96$$\sqrt{(\frac{71}{2})^2+(32)^2}$
Square root of $\sqrt{(\frac{96}{2})^2+(32)^2}$ is 57.6888204
Put The values in Area Formula:
A= $6816.0 + 71 \cdot 57.6888204 + 96$$\sqrt{(\frac{71}{2})^2 + (32)^2}$
Square Root of $\sqrt{(\frac{71}{2})^2+(32)^2}$ is 47.7938281
Put The values in Area Formula:
A= 6816.0 + 71 x 57.6888204 + 96 x 47.7938281
Multiply 71 and 57.6888204
A= 6816.0 + 4095.9062489 + 96 x 47.7938281
Multiply 96 and 47.7938281
A= 6816.0 + 4095.9062489 + 4588.2074931
Add 6816.0 and 4095.9062489
A=10911.9062489 + 4588.2074931
A= 15500.1137421 in2
∴ The Surface Area of Pyramid length 71 in , width 96 in and height 32 in is 15500.1137421 in2
Surface Area & Volume of The Pyramid Calculations
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