Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 58 centimeters by width 21 centimeters by height 29 centimeters is 3868.111839 centimeters2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 58 centimeters by width 21 centimeters by height 29 centimeters is 3868.111839 centimeters2.


    Surface Area of a Pyramid 58 cm by 21 cm by 29 cm in other units

Value unit
0.0386811 km2
0.0240354 mi2
38.6811184 m2
126.9065564 ft2
1522.8786768 in2
42.3021855 yd2
3868.111839 cm2
38681.11839 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =58 , the width w =21 , and the height h =29 into the formula for surface area of a pyramid

A=($58 \cdot21+58$$\sqrt{(\frac{21}{2})^2+(29)^2}$$+21$$\sqrt{(\frac{58}{2})^2+(29)^2}$) cm

Simplify each term.

Multiply 58 cm by 21 cm

A = $1218.0 + 58$$\sqrt{(\frac{21}{2})^2+(29)^2}$$+21$$\sqrt{(\frac{58}{2})^2+(29)^2}$

Square root of $\sqrt{(\frac{21}{2})^2+(29)^2}$ is 30.842341

Put The values in Area Formula:

A= $1218.0 + 58 \cdot 30.842341 + 21$$\sqrt{(\frac{58}{2})^2 + (29)^2}$

Square Root of $\sqrt{(\frac{58}{2})^2+(29)^2}$ is 41.0121933

Put The values in Area Formula:

A= 1218.0 + 58 x 30.842341 + 21 x 41.0121933

Multiply 58 and 30.842341

A= 1218.0 + 1788.8557795 + 21 x 41.0121933

Multiply 21 and 41.0121933

A= 1218.0 + 1788.8557795 + 861.2560595

Add 1218.0 and 1788.8557795

A=3006.8557795 + 861.2560595

A= 3868.111839 cm2

∴ The Surface Area of Pyramid length 58 cm , width 21 cm and height 29 cm is 3868.111839 cm2