Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 52 meters by width 29 inches by height 20 yards is 1003.202277 meters2 or 1211.4031556 yards2 or 1569974.5112965 inches2

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 52 meters by width 29 inches by height 20 yards is 1003.202277 meters2 or 1211.4031556 yards2 or 1569974.5112965 inches2


    Surface Area of a Pyramid 52 m by 29 in by 20 yd in other units

Value unit
1.0032023 km2
0.6233625 mi2
1003.202277 m2
3291.3460531 ft2
39496.1526378 in2
1097.115351 yd2
100320.2277 cm2
1003202.277 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l = 52 m, the width w = 29 in and the height h = 20 yd into the formula for surface area of a pyramid

      Unit Conversion of 20 yd = 18.288 m

20 Yard is 18.288 meters

To convert Yard to Meter

we know that, 1 Yard = 0.9144 Meter

To convert Yards to meters, multiply the yard value by 0.9144.

Result in Meter: 20 yd × 0.9144 × m/yd

Cancel The Comman factor of yd

Result in Meters: (20 x 0.9144 m)

Multiply 20 into 0.9144

Result in Meters: 18.288 meters

∴ 20 Yard = 18.288 meters

      Unit Conversion of 29 in = 0.7366 m

29 inches is 0.7366 meters

To convert inches to meter

we know that, 1 inch = 0.0254 meters

To convert inches to meter,multiply the inches value by 0.0254.

Result in Inches: 29 in x 0.0254 × m/in

Cancel The Comman factor of m

Result in Meters: (29 x 0.0254 m)

Multiply 29 into 0.0254

Result in meters: 0.7366 meters

∴ 29 inches = 0.7366 meters


A=($52 \cdot0.7366+52$$\sqrt{(\frac{0.7366}{2})^2+(18.288)^2}$$+0.7366$$\sqrt{(\frac{52}{2})^2+(18.288)^2}$) m

Simplify each term.

Multiply 52 m by 0.7366 m

A = $38.3032+52$$\sqrt{(\frac{0.7366}{2})^2+(18.288)^2}$$+0.7366$$\sqrt{(\frac{52}{2})^2+(18.288)^2}$

Square root of $\sqrt{(\frac{0.7366}{2})^2+(18.288)^2}$ is 18.2917082

Put The values in Area Formula:

A= $38.3032+ 52 \cdot 18.2917082+0.7366$$\sqrt{(\frac{52}{2})^2+(18.288)^2}$

Square Root of $\sqrt{(\frac{52}{2})^2+(18.288)^2}$ is 18.6400361

Put The values in Area Formula:

A= 38.3032 + (52 x 18.2917082) + (0.7366 x 18.6400361)

Multiply 52 and 18.2917082

A= 38.3032 + 951.1688264 + (0.7366 x 18.6400361)

Multiply 0.7366 and 18.6400361

A= 38.3032 + 951.1688264 + 13.7302506

Add 38.3032 and 951.1688264

A= 989.4720264 + 13.7302506

A= 1003.202277 m2

∴ The Surface Area of Pyramid length 52 m , width 29 in and height 20 yd is 1003.202277 m2

or

      Unit Conversion of 29 in = 0.8055556 yd

29 Inches is 0.8055556 yards

To convert Inche to Yards

we know that, 1 Inche = 0.02778 Yards or
                         1 Inche = 1/36 Yards

To convert Inche to Yards, divide the inche value by 36

Result in Foot: 29 × in/12 × yd/in

Cancel The Comman factor of in

Result in Foot: 29/36

Divide the 29 by 36

Result in Yards: 0.8055556 yards

∴ 29 Inches = 0.8055556 yards

      Unit Conversion of 52 m = 56.8679228 yd

52 Meter is 56.8679228 yards

To convert Meter to Yards

we know that, 1 Meter = 1.0936139 Yards

To convert Meter to Yards, multiply the mile value by 1.0936139

Result in Yards: 52 m × 1.0936139 × yd/m

Cancel The Comman factor of m

Result in Yards: (52 x 1.0936139 yd)

Multiply 52 into 1.0936139

Result in Yards: 56.8679228 yards

∴ 52 Meter = 56.8679228 yards


A=($56.8679228 \cdot0.8055556+56.8679228$$\sqrt{(\frac{0.8055556}{2})^2+(20)^2}$$+0.8055556$$\sqrt{(\frac{56.8679228}{2})^2+(20)^2}$) yd

Simplify each term.

Multiply 56.8679228 yd by 0.8055556 yd

A = $45.81027367+56.8679228$$\sqrt{(\frac{0.8055556}{2})^2+(20)^2}$$+0.8055556$$\sqrt{(\frac{56.8679228}{2})^2+(20)^2}$

Square root of $\sqrt{(\frac{0.8055556}{2})^2+(20)^2}$ is 20.0040553

Put The values in Area Formula:

A= $45.81027367+ 56.8679228 \cdot 20.0040553+0.8055556$$\sqrt{(\frac{56.8679228}{2})^2+(20)^2}$

Square Root of $\sqrt{(\frac{56.8679228}{2})^2+(20)^2}$ is 34.7633451

Put The values in Area Formula:

A= 45.8102737 + (56.8679228 x 20.0040553) + (0.8055556 x 34.7633451)

Multiply 56.8679228 and 20.0040553

A= 45.8102737 + 1137.5890746 + (0.8055556 x 34.7633451)

Multiply 0.8055556 and 34.7633451

A= 45.8102737 + 1137.5890746 + 28.0038073

Add 45.8102737 and 1137.5890746

A= 1183.3993483 + 28.0038073

A=$1211.4031556$ yd2

∴ The Surface Area of Pyramid length 52 m , width 29 in and height 20 yd is 1211.4031556 yd2

or

      Unit Conversion of 52 m = 2047.24 in

52 meter is 2047.24 inches

To convert Meters to Inches

we know that, 1 Meter = 39.37 Inch

To convert meter to Inch,multiply the meter value by 39.37.

Result in Inches: 52 m × 39.37 × in/m

Cancel The Comman factor of m

Result in Inches: (52 * 39.37 in)

Multiply 2047.24 into 39.37

∴ 52 meter = 2047.24 inches

      Unit Conversion of 20 yd = 720.0 in

20 Yards is 720.0 inches

To convert Yard to Inches

we know that, 1 Yard = 36 inches

To convert Yard to inches, multiply the yard value by 36.

Result in Yards: 20 yd x 36 × in/yd

Cancel The Comman factor of yd

Result in Inches: (20 x 36 in)

Multiply 20 into 36

Result in Inches: 720.0 inches

∴ 20 Yards = 720.0 inches


A=($2047.24 \cdot29+2047.24$$\sqrt{(\frac{29}{2})^2+(720.0)^2}$$+29$$\sqrt{(\frac{2047.24}{2})^2+(720.0)^2}$) in

Simplify each term.

Multiply 2047.24 in by 29 in

A = $59369.96+2047.24$$\sqrt{(\frac{29}{2})^2+(720.0)^2}$$+29$$\sqrt{(\frac{2047.24}{2})^2+(720.0)^2}$

Square root of $\sqrt{(\frac{29}{2})^2+(20)^2}$ is 720.1459921

Put The values in Area Formula:

A= $59369.96+ 2047.24 \cdot 720.1459921+29$$\sqrt{(\frac{2047.24}{2})^2+(720.0)^2}$

Square Root of $\sqrt{(\frac{2047.24}{2})^2+(720.0)^2}$ is 1251.4782876

Put The values in Area Formula:

A = 59369.96 + (2047.24 x 720.1459921) + (29 x 1251.4782876)

Multiply 2047.24 and 720.1459921

A = 59369.96 + 1474311.6809554 +(29 x 1251.4782876)

Multiply 29 and 1251.4782876

A= 59369.96 + 1474311.6809554 + 36292.8703412

Add 59369.96 and 1474311.6809554

A = 1533681.6409554 + 36292.8703412

A= 1569974.5112965 in2

∴ The Surface Area of Pyramid length 52 m , width 29 in and height 20 yd is 1569974.5112965 in2