Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 46 inches by width 55 inches by height 75 inches is 10519.2143256 inches2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 46 inches by width 55 inches by height 75 inches is 10519.2143256 inches2.


    Surface Area of a Pyramid 46 in by 55 in by 75 in in other units

Value unit
0.267188 km2
0.1660234 mi2
267.1880439 m2
876.6011938 ft2
10519.2143256 in2
292.2003979 yd2
26718.804387 cm2
267188.0438702 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =46 , the width w =55 , and the height h =75 into the formula for surface area of a pyramid

A=($46 \cdot55+46$$\sqrt{(\frac{55}{2})^2+(75)^2}$$+55$$\sqrt{(\frac{46}{2})^2+(75)^2}$) in

Simplify each term.

Multiply 46 in by 55 in

A = $2530.0 + 46$$\sqrt{(\frac{55}{2})^2+(75)^2}$$+55$$\sqrt{(\frac{46}{2})^2+(75)^2}$

Square root of $\sqrt{(\frac{55}{2})^2+(75)^2}$ is 79.8827265

Put The values in Area Formula:

A= $2530.0 + 46 \cdot 79.8827265 + 55$$\sqrt{(\frac{46}{2})^2 + (75)^2}$

Square Root of $\sqrt{(\frac{46}{2})^2+(75)^2}$ is 78.4474346

Put The values in Area Formula:

A= 2530.0 + 46 x 79.8827265 + 55 x 78.4474346

Multiply 46 and 79.8827265

A= 2530.0 + 3674.605421 + 55 x 78.4474346

Multiply 55 and 78.4474346

A= 2530.0 + 3674.605421 + 4314.6089046

Add 2530.0 and 3674.605421

A=6204.605421 + 4314.6089046

A= 10519.2143256 in2

∴ The Surface Area of Pyramid length 46 in , width 55 in and height 75 in is 10519.2143256 in2