Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 43 foot by width 98 foot by height 67 foot is 14679.0407083 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 43 foot by width 98 foot by height 67 foot is 14679.0407083 foot2.


    Surface Area of a Pyramid 43 ft by 98 ft by 67 ft in other units

Value unit
4.4741716 km2
2.7801283 mi2
4474.1716079 m2
14679.0407083 ft2
176148.4884996 in2
4893.0135694 yd2
447417.160789 cm2
4474171.6078898 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =43 , the width w =98 , and the height h =67 into the formula for surface area of a pyramid

A=($43 \cdot98+43$$\sqrt{(\frac{98}{2})^2+(67)^2}$$+98$$\sqrt{(\frac{43}{2})^2+(67)^2}$) ft

Simplify each term.

Multiply 43 ft by 98 ft

A = $4214.0 + 43$$\sqrt{(\frac{98}{2})^2+(67)^2}$$+98$$\sqrt{(\frac{43}{2})^2+(67)^2}$

Square root of $\sqrt{(\frac{98}{2})^2+(67)^2}$ is 83.0060239

Put The values in Area Formula:

A= $4214.0 + 43 \cdot 83.0060239 + 98$$\sqrt{(\frac{43}{2})^2 + (67)^2}$

Square Root of $\sqrt{(\frac{43}{2})^2+(67)^2}$ is 70.3651192

Put The values in Area Formula:

A= 4214.0 + 43 x 83.0060239 + 98 x 70.3651192

Multiply 43 and 83.0060239

A= 4214.0 + 3569.2590267 + 98 x 70.3651192

Multiply 98 and 70.3651192

A= 4214.0 + 3569.2590267 + 6895.7816816

Add 4214.0 and 3569.2590267

A=7783.2590267 + 6895.7816816

A= 14679.0407083 ft2

∴ The Surface Area of Pyramid length 43 ft , width 98 ft and height 67 ft is 14679.0407083 ft2