Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base(base 1)

Enter the Base (base 2)

Enter the height


The Surface Area of Pyramid 42 foot by width 98 foot by height 67 foot is 14483.220958 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 42 foot by width 98 foot by height 67 foot is 14483.220958 foot2.


    Surface Area of a Pyramid 42 ft by 98 ft by 67 ft in other units

Value unit
4.4144857 km2
2.7430411 mi2
4414.485748 m2
14483.220958 ft2
173798.651496 in2
4827.7403193 yd2
441448.5747998 cm2
4414485.7479984 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =42 , the width w =98 , and the height h =67 into the formula for surface area of a pyramid

A=($42 \cdot98+42$$\sqrt{(\frac{98}{2})^2+(67)^2}$$+98$$\sqrt{(\frac{42}{2})^2+(67)^2}$) ft

Simplify each term.

Multiply 42 ft by 98 ft

A = $4116.0 + 42$$\sqrt{(\frac{98}{2})^2+(67)^2}$$+98$$\sqrt{(\frac{42}{2})^2+(67)^2}$

Square root of $\sqrt{(\frac{98}{2})^2+(67)^2}$ is 83.0060239

Put The values in Area Formula:

A= $4116.0 + 42 \cdot 83.0060239 + 98$$\sqrt{(\frac{42}{2})^2 + (67)^2}$

Square Root of $\sqrt{(\frac{42}{2})^2+(67)^2}$ is 70.2139587

Put The values in Area Formula:

A= 4116.0 + 42 x 83.0060239 + 98 x 70.2139587

Multiply 42 and 83.0060239

A= 4116.0 + 3486.2530029 + 98 x 70.2139587

Multiply 98 and 70.2139587

A= 4116.0 + 3486.2530029 + 6880.9679552

Add 4116.0 and 3486.2530029

A=7602.2530029 + 6880.9679552

A= 14483.220958 ft2

∴ The Surface Area of Pyramid length 42 ft , width 98 ft and height 67 ft is 14483.220958 ft2