Surface area of a Pyramid 41 foot by 98 foot by 67 foot Calculator

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 41 foot by width 98 foot by height 67 foot is 14287.7189261 foot².

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =41 , the width w =98 , and the height h =67 into the formula for surface area of a pyramid

A=($41 \cdot98+41$$\sqrt{(\frac{98}{2})^2+(67)^2}$$+98$$\sqrt{(\frac{41}{2})^2+(67)^2}$) ft

Simplify each term.

Multiply 41 ft by 98 ft

A = $4018.0 + 41$$\sqrt{(\frac{98}{2})^2+(67)^2}$$+98$$\sqrt{(\frac{41}{2})^2+(67)^2}$

Square root of $\sqrt{(\frac{98}{2})^2+(67)^2}$ is 83.0060239

Put The values in Area Formula:

A= $4018.0 + 41 \cdot 83.0060239 + 98$$\sqrt{(\frac{41}{2})^2 + (67)^2}$

Square Root of $\sqrt{(\frac{41}{2})^2+(67)^2}$ is 70.0660403

Put The values in Area Formula:

A= 4018.0 + 41 x 83.0060239 + 98 x 70.0660403

Multiply 41 and 83.0060239

A= 4018.0 + 3403.246979 + 98 x 70.0660403

Multiply 98 and 70.0660403

A= 4018.0 + 3403.246979 + 6866.4719471

Add 4018.0 and 3403.246979

A=7421.246979 + 6866.4719471

A= 14287.7189261 ft²

∴ The Surface Area of Pyramid length 41 ft , width 98 ft and height 67 ft is 14287.7189261 ft²