Surface area of a Pyramid 40 foot by 98 foot by 72 foot Calculator

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 40 foot by width 98 foot by height 72 foot is 14726.8405625 foot².

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =40 , the width w =98 , and the height h =72 into the formula for surface area of a pyramid

A=($40 \cdot98+40$$\sqrt{(\frac{98}{2})^2+(72)^2}$$+98$$\sqrt{(\frac{40}{2})^2+(72)^2}$) ft

Simplify each term.

Multiply 40 ft by 98 ft

A = $3920.0 + 40$$\sqrt{(\frac{98}{2})^2+(72)^2}$$+98$$\sqrt{(\frac{40}{2})^2+(72)^2}$

Square root of $\sqrt{(\frac{98}{2})^2+(72)^2}$ is 87.0919055

Put The values in Area Formula:

A= $3920.0 + 40 \cdot 87.0919055 + 98$$\sqrt{(\frac{40}{2})^2 + (72)^2}$

Square Root of $\sqrt{(\frac{40}{2})^2+(72)^2}$ is 74.7261668

Put The values in Area Formula:

A= 3920.0 + 40 x 87.0919055 + 98 x 74.7261668

Multiply 40 and 87.0919055

A= 3920.0 + 3483.6762192 + 98 x 74.7261668

Multiply 98 and 74.7261668

A= 3920.0 + 3483.6762192 + 7323.1643434

Add 3920.0 and 3483.6762192

A=7403.6762192 + 7323.1643434

A= 14726.8405625 ft²

∴ The Surface Area of Pyramid length 40 ft , width 98 ft and height 72 ft is 14726.8405625 ft²