Surface area of a Pyramid 40 foot by 98 foot by 71 foot Calculator
The Surface Area of Pyramid 40 foot by width 98 foot by height 71 foot is 14599.4682657 foot2.
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 40 foot by width 98 foot by height 71 foot is 14599.4682657 foot2.
Surface Area of a Pyramid 40 ft by 98 ft by 71 ft in other units
Value | unit |
---|---|
4.4499179 | km2 |
2.7650577 | mi2 |
4449.9179274 | m2 |
14599.4682657 | ft2 |
175193.6191884 | in2 |
4866.4894219 | yd2 |
444991.7927385 | cm2 |
4449917.9273854 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =40 , the width w =98 , and the height h =71 into the formula for surface area of a pyramid
A=($40 \cdot98+40$$\sqrt{(\frac{98}{2})^2+(71)^2}$$+98$$\sqrt{(\frac{40}{2})^2+(71)^2}$) ft
Simplify each term.
Multiply 40 ft by 98 ft
A = $3920.0 + 40$$\sqrt{(\frac{98}{2})^2+(71)^2}$$+98$$\sqrt{(\frac{40}{2})^2+(71)^2}$
Square root of $\sqrt{(\frac{98}{2})^2+(71)^2}$ is 86.2670273
Put The values in Area Formula:
A= $3920.0 + 40 \cdot 86.2670273 + 98$$\sqrt{(\frac{40}{2})^2 + (71)^2}$
Square Root of $\sqrt{(\frac{40}{2})^2+(71)^2}$ is 73.7631344
Put The values in Area Formula:
A= 3920.0 + 40 x 86.2670273 + 98 x 73.7631344
Multiply 40 and 86.2670273
A= 3920.0 + 3450.6810922 + 98 x 73.7631344
Multiply 98 and 73.7631344
A= 3920.0 + 3450.6810922 + 7228.7871735
Add 3920.0 and 3450.6810922
A=7370.6810922 + 7228.7871735
A= 14599.4682657 ft2
∴ The Surface Area of Pyramid length 40 ft , width 98 ft and height 71 ft is 14599.4682657 ft2