Surface area of a Pyramid 40 foot by 98 foot by 69 foot Calculator
The Surface Area of Pyramid 40 foot by width 98 foot by height 69 foot is 14345.4738365 foot2.
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 40 foot by width 98 foot by height 69 foot is 14345.4738365 foot2.
Surface Area of a Pyramid 40 ft by 98 ft by 69 ft in other units
Value | unit |
---|---|
4.3725004 | km2 |
2.7169526 | mi2 |
4372.5004254 | m2 |
14345.4738365 | ft2 |
172145.686038 | in2 |
4781.8246122 | yd2 |
437250.0425365 | cm2 |
4372500.4253652 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =40 , the width w =98 , and the height h =69 into the formula for surface area of a pyramid
A=($40 \cdot98+40$$\sqrt{(\frac{98}{2})^2+(69)^2}$$+98$$\sqrt{(\frac{40}{2})^2+(69)^2}$) ft
Simplify each term.
Multiply 40 ft by 98 ft
A = $3920.0 + 40$$\sqrt{(\frac{98}{2})^2+(69)^2}$$+98$$\sqrt{(\frac{40}{2})^2+(69)^2}$
Square root of $\sqrt{(\frac{98}{2})^2+(69)^2}$ is 84.6286004
Put The values in Area Formula:
A= $3920.0 + 40 \cdot 84.6286004 + 98$$\sqrt{(\frac{40}{2})^2 + (69)^2}$
Square Root of $\sqrt{(\frac{40}{2})^2+(69)^2}$ is 71.8401002
Put The values in Area Formula:
A= 3920.0 + 40 x 84.6286004 + 98 x 71.8401002
Multiply 40 and 84.6286004
A= 3920.0 + 3385.1440147 + 98 x 71.8401002
Multiply 98 and 71.8401002
A= 3920.0 + 3385.1440147 + 7040.3298218
Add 3920.0 and 3385.1440147
A=7305.1440147 + 7040.3298218
A= 14345.4738365 ft2
∴ The Surface Area of Pyramid length 40 ft , width 98 ft and height 69 ft is 14345.4738365 ft2