Surface area of a Pyramid 40 foot by 98 foot by 68 foot Calculator

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 40 foot by width 98 foot by height 68 foot is 14218.8686203 foot².

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =40 , the width w =98 , and the height h =68 into the formula for surface area of a pyramid

A=($40 \cdot98+40$$\sqrt{(\frac{98}{2})^2+(68)^2}$$+98$$\sqrt{(\frac{40}{2})^2+(68)^2}$) ft

Simplify each term.

Multiply 40 ft by 98 ft

A = $3920.0 + 40$$\sqrt{(\frac{98}{2})^2+(68)^2}$$+98$$\sqrt{(\frac{40}{2})^2+(68)^2}$

Square root of $\sqrt{(\frac{98}{2})^2+(68)^2}$ is 83.8152731

Put The values in Area Formula:

A= $3920.0 + 40 \cdot 83.8152731 + 98$$\sqrt{(\frac{40}{2})^2 + (68)^2}$

Square Root of $\sqrt{(\frac{40}{2})^2+(68)^2}$ is 70.8801806

Put The values in Area Formula:

A= 3920.0 + 40 x 83.8152731 + 98 x 70.8801806

Multiply 40 and 83.8152731

A= 3920.0 + 3352.6109228 + 98 x 70.8801806

Multiply 98 and 70.8801806

A= 3920.0 + 3352.6109228 + 6946.2576975

Add 3920.0 and 3352.6109228

A=7272.6109228 + 6946.2576975

A= 14218.8686203 ft²

∴ The Surface Area of Pyramid length 40 ft , width 98 ft and height 68 ft is 14218.8686203 ft²