Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base(base 1)

Enter the Base (base 2)

Enter the height


The Surface Area of Pyramid 4 centimeters by width 4 centimeters by height 5 centimeters is 59.0813185 centimeters2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 4 centimeters by width 4 centimeters by height 5 centimeters is 59.0813185 centimeters2.


    Surface Area of a Pyramid 4 cm by 4 cm by 5 cm in other units

Value unit
0.0005908 km2
0.0003671 mi2
0.5908132 m2
1.9383635 ft2
23.2603616 in2
0.6461212 yd2
59.0813185 cm2
590.813185 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =4 , the width w =4 , and the height h =5 into the formula for surface area of a pyramid

A=($4 \cdot4+4$$\sqrt{(\frac{4}{2})^2+(5)^2}$$+4$$\sqrt{(\frac{4}{2})^2+(5)^2}$) cm

Simplify each term.

Multiply 4 cm by 4 cm

A = $16.0 + 4$$\sqrt{(\frac{4}{2})^2+(5)^2}$$+4$$\sqrt{(\frac{4}{2})^2+(5)^2}$

Square root of $\sqrt{(\frac{4}{2})^2+(5)^2}$ is 5.3851648

Put The values in Area Formula:

A= $16.0 + 4 \cdot 5.3851648 + 4$$\sqrt{(\frac{4}{2})^2 + (5)^2}$

Square Root of $\sqrt{(\frac{4}{2})^2+(5)^2}$ is 5.3851648

Put The values in Area Formula:

A= 16.0 + 4 x 5.3851648 + 4 x 5.3851648

Multiply 4 and 5.3851648

A= 16.0 + 21.5406592 + 4 x 5.3851648

Multiply 4 and 5.3851648

A= 16.0 + 21.5406592 + 21.5406592

Add 16.0 and 21.5406592

A=37.5406592 + 21.5406592

A= 59.0813185 cm2

∴ The Surface Area of Pyramid length 4 cm , width 4 cm and height 5 cm is 59.0813185 cm2