Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 18 inches by width 39 inches by height 37 inches is 2939.9084064 inches2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 18 inches by width 39 inches by height 37 inches is 2939.9084064 inches2.


    Surface Area of a Pyramid 18 in by 39 in by 37 in in other units

Value unit
0.0746737 km2
0.0464002 mi2
74.6736735 m2
244.9923672 ft2
2939.9084064 in2
81.6641224 yd2
7467.3673523 cm2
74673.6735226 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =18 , the width w =39 , and the height h =37 into the formula for surface area of a pyramid

A=($18 \cdot39+18$$\sqrt{(\frac{39}{2})^2+(37)^2}$$+39$$\sqrt{(\frac{18}{2})^2+(37)^2}$) in

Simplify each term.

Multiply 18 in by 39 in

A = $702.0 + 18$$\sqrt{(\frac{39}{2})^2+(37)^2}$$+39$$\sqrt{(\frac{18}{2})^2+(37)^2}$

Square root of $\sqrt{(\frac{39}{2})^2+(37)^2}$ is 41.8240362

Put The values in Area Formula:

A= $702.0 + 18 \cdot 41.8240362 + 39$$\sqrt{(\frac{18}{2})^2 + (37)^2}$

Square Root of $\sqrt{(\frac{18}{2})^2+(37)^2}$ is 38.0788655

Put The values in Area Formula:

A= 702.0 + 18 x 41.8240362 + 39 x 38.0788655

Multiply 18 and 41.8240362

A= 702.0 + 752.8326507 + 39 x 38.0788655

Multiply 39 and 38.0788655

A= 702.0 + 752.8326507 + 1485.0757556

Add 702.0 and 752.8326507

A=1454.8326507 + 1485.0757556

A= 2939.9084064 in2

∴ The Surface Area of Pyramid length 18 in , width 39 in and height 37 in is 2939.9084064 in2