Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 13 inches by width 39 inches by height 42 inches is 2766.4786126 inches2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 13 inches by width 39 inches by height 42 inches is 2766.4786126 inches2.


    Surface Area of a Pyramid 13 in by 39 in by 42 in in other units

Value unit
0.0702686 km2
0.043663 mi2
70.2685568 m2
230.5398844 ft2
2766.4786126 in2
76.8466281 yd2
7026.855676 cm2
70268.55676 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =13 , the width w =39 , and the height h =42 into the formula for surface area of a pyramid

A=($13 \cdot39+13$$\sqrt{(\frac{39}{2})^2+(42)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(42)^2}$) in

Simplify each term.

Multiply 13 in by 39 in

A = $507.0 + 13$$\sqrt{(\frac{39}{2})^2+(42)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(42)^2}$

Square root of $\sqrt{(\frac{39}{2})^2+(42)^2}$ is 46.3060471

Put The values in Area Formula:

A= $507.0 + 13 \cdot 46.3060471 + 39$$\sqrt{(\frac{13}{2})^2 + (42)^2}$

Square Root of $\sqrt{(\frac{13}{2})^2+(42)^2}$ is 42.5

Put The values in Area Formula:

A= 507.0 + 13 x 46.3060471 + 39 x 42.5

Multiply 13 and 46.3060471

A= 507.0 + 601.9786126 + 39 x 42.5

Multiply 39 and 42.5

A= 507.0 + 601.9786126 + 1657.5

Add 507.0 and 601.9786126

A=1108.9786126 + 1657.5

A= 2766.4786126 in2

∴ The Surface Area of Pyramid length 13 in , width 39 in and height 42 in is 2766.4786126 in2