Surface area of a Pyramid 13 inches by 39 inches by 41 inches Calculator
The Surface Area of Pyramid 13 inches by width 39 inches by height 41 inches is 2716.1826967 inches2.
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 13 inches by width 39 inches by height 41 inches is 2716.1826967 inches2.
Surface Area of a Pyramid 13 in by 39 in by 41 in in other units
Value | unit |
---|---|
0.068991 | km2 |
0.0428692 | mi2 |
68.9910405 | m2 |
226.3485581 | ft2 |
2716.1826967 | in2 |
75.4495194 | yd2 |
6899.1040496 | cm2 |
68991.0404962 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =13 , the width w =39 , and the height h =41 into the formula for surface area of a pyramid
A=($13 \cdot39+13$$\sqrt{(\frac{39}{2})^2+(41)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(41)^2}$) in
Simplify each term.
Multiply 13 in by 39 in
A = $507.0 + 13$$\sqrt{(\frac{39}{2})^2+(41)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(41)^2}$
Square root of $\sqrt{(\frac{39}{2})^2+(41)^2}$ is 45.4009912
Put The values in Area Formula:
A= $507.0 + 13 \cdot 45.4009912 + 39$$\sqrt{(\frac{13}{2})^2 + (41)^2}$
Square Root of $\sqrt{(\frac{13}{2})^2+(41)^2}$ is 41.5120464
Put The values in Area Formula:
A= 507.0 + 13 x 45.4009912 + 39 x 41.5120464
Multiply 13 and 45.4009912
A= 507.0 + 590.2128853 + 39 x 41.5120464
Multiply 39 and 41.5120464
A= 507.0 + 590.2128853 + 1618.9698113
Add 507.0 and 590.2128853
A=1097.2128853 + 1618.9698113
A= 2716.1826967 in2
∴ The Surface Area of Pyramid length 13 in , width 39 in and height 41 in is 2716.1826967 in2