Surface area of a Pyramid 13 inches by 39 inches by 40 inches Calculator

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 13 inches by width 39 inches by height 40 inches is 2665.9626696 inches².

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =13 , the width w =39 , and the height h =40 into the formula for surface area of a pyramid

A=($13 \cdot39+13$$\sqrt{(\frac{39}{2})^2+(40)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(40)^2}$) in

Simplify each term.

Multiply 13 in by 39 in

A = $507.0 + 13$$\sqrt{(\frac{39}{2})^2+(40)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(40)^2}$

Square root of $\sqrt{(\frac{39}{2})^2+(40)^2}$ is 44.5

Put The values in Area Formula:

A= $507.0 + 13 \cdot 44.5 + 39$$\sqrt{(\frac{13}{2})^2 + (40)^2}$

Square Root of $\sqrt{(\frac{13}{2})^2+(40)^2}$ is 40.5246838

Put The values in Area Formula:

A= 507.0 + 13 x 44.5 + 39 x 40.5246838

Multiply 13 and 44.5

A= 507.0 + 578.5 + 39 x 40.5246838

Multiply 39 and 40.5246838

A= 507.0 + 578.5 + 1580.4626696

Add 507.0 and 578.5

A=1085.5 + 1580.4626696

A= 2665.9626696 in²

∴ The Surface Area of Pyramid length 13 in , width 39 in and height 40 in is 2665.9626696 in²