Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 13 inches by width 39 inches by height 39 inches is 2615.8235337 inches2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 13 inches by width 39 inches by height 39 inches is 2615.8235337 inches2.


    Surface Area of a Pyramid 13 in by 39 in by 39 in in other units

Value unit
0.0664419 km2
0.0412852 mi2
66.4419178 m2
217.9852945 ft2
2615.8235337 in2
72.6617648 yd2
6644.1917756 cm2
66441.917756 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =13 , the width w =39 , and the height h =39 into the formula for surface area of a pyramid

A=($13 \cdot39+13$$\sqrt{(\frac{39}{2})^2+(39)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(39)^2}$) in

Simplify each term.

Multiply 13 in by 39 in

A = $507.0 + 13$$\sqrt{(\frac{39}{2})^2+(39)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(39)^2}$

Square root of $\sqrt{(\frac{39}{2})^2+(39)^2}$ is 43.6033256

Put The values in Area Formula:

A= $507.0 + 13 \cdot 43.6033256 + 39$$\sqrt{(\frac{13}{2})^2 + (39)^2}$

Square Root of $\sqrt{(\frac{13}{2})^2+(39)^2}$ is 39.5379564

Put The values in Area Formula:

A= 507.0 + 13 x 43.6033256 + 39 x 39.5379564

Multiply 13 and 43.6033256

A= 507.0 + 566.8432323 + 39 x 39.5379564

Multiply 39 and 39.5379564

A= 507.0 + 566.8432323 + 1541.9803014

Add 507.0 and 566.8432323

A=1073.8432323 + 1541.9803014

A= 2615.8235337 in2

∴ The Surface Area of Pyramid length 13 in , width 39 in and height 39 in is 2615.8235337 in2