Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 13 inches by width 39 inches by height 38 inches is 2565.7707256 inches2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 13 inches by width 39 inches by height 38 inches is 2565.7707256 inches2.


    Surface Area of a Pyramid 13 in by 39 in by 38 in in other units

Value unit
0.0651706 km2
0.0404952 mi2
65.1705764 m2
213.8142271 ft2
2565.7707256 in2
71.271409 yd2
6517.057643 cm2
65170.5764302 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =13 , the width w =39 , and the height h =38 into the formula for surface area of a pyramid

A=($13 \cdot39+13$$\sqrt{(\frac{39}{2})^2+(38)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(38)^2}$) in

Simplify each term.

Multiply 13 in by 39 in

A = $507.0 + 13$$\sqrt{(\frac{39}{2})^2+(38)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(38)^2}$

Square root of $\sqrt{(\frac{39}{2})^2+(38)^2}$ is 42.7112397

Put The values in Area Formula:

A= $507.0 + 13 \cdot 42.7112397 + 39$$\sqrt{(\frac{13}{2})^2 + (38)^2}$

Square Root of $\sqrt{(\frac{13}{2})^2+(38)^2}$ is 38.5519131

Put The values in Area Formula:

A= 507.0 + 13 x 42.7112397 + 39 x 38.5519131

Multiply 13 and 42.7112397

A= 507.0 + 555.2461166 + 39 x 38.5519131

Multiply 39 and 38.5519131

A= 507.0 + 555.2461166 + 1503.524609

Add 507.0 and 555.2461166

A=1062.2461166 + 1503.524609

A= 2565.7707256 in2

∴ The Surface Area of Pyramid length 13 in , width 39 in and height 38 in is 2565.7707256 in2