Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 13 inches by width 39 inches by height 37 inches is 2515.810163 inches2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 13 inches by width 39 inches by height 37 inches is 2515.810163 inches2.


    Surface Area of a Pyramid 13 in by 39 in by 37 in in other units

Value unit
0.0639016 km2
0.0397067 mi2
63.9015781 m2
209.6508469 ft2
2515.810163 in2
69.8836156 yd2
6390.157814 cm2
63901.5781402 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =13 , the width w =39 , and the height h =37 into the formula for surface area of a pyramid

A=($13 \cdot39+13$$\sqrt{(\frac{39}{2})^2+(37)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(37)^2}$) in

Simplify each term.

Multiply 13 in by 39 in

A = $507.0 + 13$$\sqrt{(\frac{39}{2})^2+(37)^2}$$+39$$\sqrt{(\frac{13}{2})^2+(37)^2}$

Square root of $\sqrt{(\frac{39}{2})^2+(37)^2}$ is 41.8240362

Put The values in Area Formula:

A= $507.0 + 13 \cdot 41.8240362 + 39$$\sqrt{(\frac{13}{2})^2 + (37)^2}$

Square Root of $\sqrt{(\frac{13}{2})^2+(37)^2}$ is 37.5666075

Put The values in Area Formula:

A= 507.0 + 13 x 41.8240362 + 39 x 37.5666075

Multiply 13 and 41.8240362

A= 507.0 + 543.71247 + 39 x 37.5666075

Multiply 39 and 37.5666075

A= 507.0 + 543.71247 + 1465.097693

Add 507.0 and 543.71247

A=1050.71247 + 1465.097693

A= 2515.810163 in2

∴ The Surface Area of Pyramid length 13 in , width 39 in and height 37 in is 2515.810163 in2