Surface area of a Pyramid 10 foot by 93 foot by 28 foot Calculator
The Surface Area of Pyramid 10 foot by width 93 foot by height 28 foot is 4117.9857528 foot2.
The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 10 foot by width 93 foot by height 28 foot is 4117.9857528 foot2.
Surface Area of a Pyramid 10 ft by 93 ft by 28 ft in other units
Value | unit |
---|---|
1.2551621 | km2 |
0.7799235 | mi2 |
1255.1620575 | m2 |
4117.9857528 | ft2 |
49415.8290336 | in2 |
1372.6619176 | yd2 |
125516.2057453 | cm2 |
1255162.0574534 | mm2 |
Steps:
The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$
Substitute the values of the length l =10 , the width w =93 , and the height h =28 into the formula for surface area of a pyramid
A=($10 \cdot93+10$$\sqrt{(\frac{93}{2})^2+(28)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(28)^2}$) ft
Simplify each term.
Multiply 10 ft by 93 ft
A = $930.0 + 10$$\sqrt{(\frac{93}{2})^2+(28)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(28)^2}$
Square root of $\sqrt{(\frac{93}{2})^2+(28)^2}$ is 54.2793699
Put The values in Area Formula:
A= $930.0 + 10 \cdot 54.2793699 + 93$$\sqrt{(\frac{10}{2})^2 + (28)^2}$
Square Root of $\sqrt{(\frac{10}{2})^2+(28)^2}$ is 28.4429253
Put The values in Area Formula:
A= 930.0 + 10 x 54.2793699 + 93 x 28.4429253
Multiply 10 and 54.2793699
A= 930.0 + 542.7936993 + 93 x 28.4429253
Multiply 93 and 28.4429253
A= 930.0 + 542.7936993 + 2645.1920535
Add 930.0 and 542.7936993
A=1472.7936993 + 2645.1920535
A= 4117.9857528 ft2
∴ The Surface Area of Pyramid length 10 ft , width 93 ft and height 28 ft is 4117.9857528 ft2