Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 10 foot by width 93 foot by height 28 foot is 4117.9857528 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 10 foot by width 93 foot by height 28 foot is 4117.9857528 foot2.


    Surface Area of a Pyramid 10 ft by 93 ft by 28 ft in other units

Value unit
1.2551621 km2
0.7799235 mi2
1255.1620575 m2
4117.9857528 ft2
49415.8290336 in2
1372.6619176 yd2
125516.2057453 cm2
1255162.0574534 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =10 , the width w =93 , and the height h =28 into the formula for surface area of a pyramid

A=($10 \cdot93+10$$\sqrt{(\frac{93}{2})^2+(28)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(28)^2}$) ft

Simplify each term.

Multiply 10 ft by 93 ft

A = $930.0 + 10$$\sqrt{(\frac{93}{2})^2+(28)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(28)^2}$

Square root of $\sqrt{(\frac{93}{2})^2+(28)^2}$ is 54.2793699

Put The values in Area Formula:

A= $930.0 + 10 \cdot 54.2793699 + 93$$\sqrt{(\frac{10}{2})^2 + (28)^2}$

Square Root of $\sqrt{(\frac{10}{2})^2+(28)^2}$ is 28.4429253

Put The values in Area Formula:

A= 930.0 + 10 x 54.2793699 + 93 x 28.4429253

Multiply 10 and 54.2793699

A= 930.0 + 542.7936993 + 93 x 28.4429253

Multiply 93 and 28.4429253

A= 930.0 + 542.7936993 + 2645.1920535

Add 930.0 and 542.7936993

A=1472.7936993 + 2645.1920535

A= 4117.9857528 ft2

∴ The Surface Area of Pyramid length 10 ft , width 93 ft and height 28 ft is 4117.9857528 ft2