Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 10 foot by width 93 foot by height 25 foot is 3828.9881997 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 10 foot by width 93 foot by height 25 foot is 3828.9881997 foot2.


    Surface Area of a Pyramid 10 ft by 93 ft by 25 ft in other units

Value unit
1.1670756 km2
0.725189 mi2
1167.0756033 m2
3828.9881997 ft2
45947.8583964 in2
1276.3293999 yd2
116707.5603269 cm2
1167075.6032686 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =10 , the width w =93 , and the height h =25 into the formula for surface area of a pyramid

A=($10 \cdot93+10$$\sqrt{(\frac{93}{2})^2+(25)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(25)^2}$) ft

Simplify each term.

Multiply 10 ft by 93 ft

A = $930.0 + 10$$\sqrt{(\frac{93}{2})^2+(25)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(25)^2}$

Square root of $\sqrt{(\frac{93}{2})^2+(25)^2}$ is 52.7944126

Put The values in Area Formula:

A= $930.0 + 10 \cdot 52.7944126 + 93$$\sqrt{(\frac{10}{2})^2 + (25)^2}$

Square Root of $\sqrt{(\frac{10}{2})^2+(25)^2}$ is 25.4950976

Put The values in Area Formula:

A= 930.0 + 10 x 52.7944126 + 93 x 25.4950976

Multiply 10 and 52.7944126

A= 930.0 + 527.9441258 + 93 x 25.4950976

Multiply 93 and 25.4950976

A= 930.0 + 527.9441258 + 2371.0440738

Add 930.0 and 527.9441258

A=1457.9441258 + 2371.0440738

A= 3828.9881997 ft2

∴ The Surface Area of Pyramid length 10 ft , width 93 ft and height 25 ft is 3828.9881997 ft2