Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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The Surface Area of Pyramid 10 foot by width 93 foot by height 24 foot is 3733.2059313 foot2.

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area l x w , and sl and sw represent the slant height on the length and slant height on the width. If the Pyramid has a length 10 foot by width 93 foot by height 24 foot is 3733.2059313 foot2.


    Surface Area of a Pyramid 10 ft by 93 ft by 24 ft in other units

Value unit
1.1378812 km2
0.7070483 mi2
1137.8811679 m2
3733.2059313 ft2
44798.4711756 in2
1244.4019771 yd2
113788.116786 cm2
1137881.1678602 mm2

Steps:

The Surface area of Pyramid A = $lw+l$$\sqrt{(\frac{w}{2})^2+(h)^2}$$+w$$\sqrt{(\frac{l}{2})^2+(h)^2}$

Substitute the values of the length l =10 , the width w =93 , and the height h =24 into the formula for surface area of a pyramid

A=($10 \cdot93+10$$\sqrt{(\frac{93}{2})^2+(24)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(24)^2}$) ft

Simplify each term.

Multiply 10 ft by 93 ft

A = $930.0 + 10$$\sqrt{(\frac{93}{2})^2+(24)^2}$$+93$$\sqrt{(\frac{10}{2})^2+(24)^2}$

Square root of $\sqrt{(\frac{93}{2})^2+(24)^2}$ is 52.3282906

Put The values in Area Formula:

A= $930.0 + 10 \cdot 52.3282906 + 93$$\sqrt{(\frac{10}{2})^2 + (24)^2}$

Square Root of $\sqrt{(\frac{10}{2})^2+(24)^2}$ is 24.5153013

Put The values in Area Formula:

A= 930.0 + 10 x 52.3282906 + 93 x 24.5153013

Multiply 10 and 52.3282906

A= 930.0 + 523.2829063 + 93 x 24.5153013

Multiply 93 and 24.5153013

A= 930.0 + 523.2829063 + 2279.923025

Add 930.0 and 523.2829063

A=1453.2829063 + 2279.923025

A= 3733.2059313 ft2

∴ The Surface Area of Pyramid length 10 ft , width 93 ft and height 24 ft is 3733.2059313 ft2