Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of Length(l)

Enter the value of Width(w)

Enter the value of Height(h)


Surface area of a Box length 27 foot by width 64 foot by height 58 foot is 14012.0 foot2.

The Surface Area of a Box is equal to the sum of the areas of each side of the box. If the box has a length 27 foot by width 64 foot by height 58 foot is 14012.0 foot2.


    Surface Area of a Box 27 ft by 64 ft by 58 ft in other units

Value unit
4.2708576 km2
2.6537945 mi2
4270.8576 m2
14012.0 ft2
168144.0 in2
4670.6666667 yd2
427085.76 cm2
4270857.6 mm2

Steps:

The Surface Area of a Box 2 * (length * width) + 2 * (length * height) + 2 * (width * height)

Substitute the values of the length l = 27 ft , the width w = 64 ft , and the height h = 58 ft into the formula

2 * (27 ft * 64 ft) + 2 * (27 ft* 58 ft) + 2 * (64 ft* 58 ft)

Simplify each term

2 * 1728.0 ft2 + 2 * 1566.0 ft2 + 2 * 3712.0 ft2

Multiply each term with 2

3456.0 ft2 + 3132.0 ft2 + 7424.0 ft2

Simplify by adding three(3) term or numbers

Surface area = 14012.0 ft2

∴ Surface area of a Box length 27 ft , width 64 ft and height 58 ft is 14012.0 ft2