Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base(base 1)

Enter the Base (base 2)

Enter the Base(base 3)


Perimeter of a Triangle whose sides are 49 inches, 47 inches and 22 inches is 118.0 inches.

The perimeter of a triangle is the distance covered around the triangle and is calculated as the sum of all the three sides of it. Perimeter of a Triangle whose sides are 49 inches, 47 inches and 22 inches is 118.0 inches.


    Perimeter of a Triangle 49 in by 47 in by 22 in in other units

Value unit
0.0029972 km
0.0018624 mi
2.9972 m
9.8333333 ft
118.0 in
3.2777778 yd
299.72 cm
2997.2 mm

Steps:

Given triangle sides are 49 in, 47 in and 22 in:

Let a = 49 in, b = 47 in and c = 22 in

Perimeter = Sum of all sides = a + b + c

Perimeter = 49 in + 47 in + 22 in = 118.0 in

∴ Perimeter of a Triangle whose sides are 49 in, 47 in and 22 in is 118.0 in