Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the length

Enter the width


Perimeter of rectangle 71 foot by 53 foot is 248.0 foot.

The perimeter of a rectangle is defined as the sum of all the sides of a rectangle. Perimeter of a rectangle = 2 (Length + Width) units. Perimeter of rectangle 71 foot by 53 foot is 248.0 foot.


    Perimeter of Rectangle 71 ft by 53 ft in other units

Value unit
0.0755904 km
0.0469698 mi
75.5904 m
248.0 ft
2976.0 in
82.6666667 yd
7559.04 cm
75590.4 mm

Steps:

Given that length = 71 ft and width =53 ft

Perimeter = 2 x (length + width)

Put the value of length and width value in Perimeter Formula.

Perimeter = 2 x ( 71 ft + 53 ft)

Add 71 ft and 53 ft

Perimeter = 2 x (124.0) ft

Multiply 2 and 124.0 ft

Perimeter = 248.0 ft

∴Perimeter of Rectangle 71 ft by 53 ft is 248.0 ft