Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (base 1)

Enter the Base (base 2)

Enter the height


Area of a Trapezoid 82 centimeters,71 and 26 is 1989.0 centimeters2

Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 82 centimeters,base2 71 and 26 is 1989.0 centimeters2


    Area of Trapezoid 82 cm by 71 cm by 26 cm in other units

Value unit
0.01989 km2
0.0123591 mi2
19.89 m2
65.2559055 ft2
783.0708661 in2
21.7519685 yd2
1989.0 cm2
19890.0 mm2

Steps:

Given that base1 = 82 cm and base2 = 71 cm and height =26 cm

Substitute the values of the bases(b1 = 82 cm and b2 = 71 cm) and height h = 26 26 into the formula for the area of a trapezoid.

Area = $1\above 1pt2$ * height * (base1 +base2)

Put the value of base and height value in Area Formula.

Area = $1\above 1pt2$ * (26 cm) * (82 + 71) cm

Add the bases value b1 = 82 cm and b2 = 71 cm

Area = $1\above 1pt2$ * 26 cm * (153.0 cm)

Multiply 26 cm and 153.0 cm

Area = $1\above 1pt2$ * 3978.0 cm2

Divide 3978.0 cm by 2

Area = 1989.0 cm2

∴ Area of a Trapezoid 82 cm by 71 cm by 26 cm is 1989.0 cm2