Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (base 1)

Enter the Base (base 2)

Enter the height


Area of a Trapezoid 68 centimeters,12 and 30 is 1200.0 centimeters2

Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 68 centimeters,base2 12 and 30 is 1200.0 centimeters2


    Area of Trapezoid 68 cm by 12 cm by 30 cm in other units

Value unit
0.012 km2
0.0074565 mi2
12.0 m2
39.3700787 ft2
472.4409449 in2
13.1233596 yd2
1200.0 cm2
12000.0 mm2

Steps:

Given that base1 = 68 cm and base2 = 12 cm and height =30 cm

Substitute the values of the bases(b1 = 68 cm and b2 = 12 cm) and height h = 30 30 into the formula for the area of a trapezoid.

Area = $1\above 1pt2$ * height * (base1 +base2)

Put the value of base and height value in Area Formula.

Area = $1\above 1pt2$ * (30 cm) * (68 + 12) cm

Add the bases value b1 = 68 cm and b2 = 12 cm

Area = $1\above 1pt2$ * 30 cm * (80.0 cm)

Multiply 30 cm and 80.0 cm

Area = $1\above 1pt2$ * 2400.0 cm2

Divide 2400.0 cm by 2

Area = 1200.0 cm2

∴ Area of a Trapezoid 68 cm by 12 cm by 30 cm is 1200.0 cm2