Area of a Trapezoid 63 meters by 40 meters by 17 meters Calculator
Area of a Trapezoid 63 meters,40 and 17 is 875.5 meters2
Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 63 meters,base2 40 and 17 is 875.5 meters2
Area of Trapezoid 63 m by 40 m by 17 m in other units
| Value | unit |
|---|---|
| 0.8755 | km2 |
| 0.5440118 | mi2 |
| 875.5 | m2 |
| 2872.3753281 | ft2 |
| 34468.503937 | in2 |
| 957.4584427 | yd2 |
| 87550.0 | cm2 |
| 875500.0 | mm2 |
Steps:
Given that base1 = 63 m and base2 = 40 m and height =17 m
Substitute the values of the bases(b1 = 63 m and b2 = 40 m) and height h = 17 17 into the formula for the area of a trapezoid.
Area = $1\above 1pt2$ * height * (base1 +base2)
Put the value of base and height value in Area Formula.
Area = $1\above 1pt2$ * (17 m) * (63 + 40) m
Add the bases value b1 = 63 m and b2 = 40 m
Area = $1\above 1pt2$ * 17 m * (103.0 m)
Multiply 17 m and 103.0 m
Area = $1\above 1pt2$ * 1751.0 m2
Divide 1751.0 m by 2
Area = 875.5 m2
∴ Area of a Trapezoid 63 m by 40 m by 17 m is 875.5 m2