Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (base 1)

Enter the Base (base 2)

Enter the height


Area of a Trapezoid 55 meters,30 and 14 is 595.0 meters2

Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 55 meters,base2 30 and 14 is 595.0 meters2


    Area of Trapezoid 55 m by 30 m by 14 m in other units

Value unit
0.595 km2
0.3697168 mi2
595.0 m2
1952.0997375 ft2
23425.1968504 in2
650.6999125 yd2
59500.0 cm2
595000.0 mm2

Steps:

Given that base1 = 55 m and base2 = 30 m and height =14 m

Substitute the values of the bases(b1 = 55 m and b2 = 30 m) and height h = 14 14 into the formula for the area of a trapezoid.

Area = $1\above 1pt2$ * height * (base1 +base2)

Put the value of base and height value in Area Formula.

Area = $1\above 1pt2$ * (14 m) * (55 + 30) m

Add the bases value b1 = 55 m and b2 = 30 m

Area = $1\above 1pt2$ * 14 m * (85.0 m)

Multiply 14 m and 85.0 m

Area = $1\above 1pt2$ * 1190.0 m2

Divide 1190.0 m by 2

Area = 595.0 m2

∴ Area of a Trapezoid 55 m by 30 m by 14 m is 595.0 m2