Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (base 1)

Enter the Base (base 2)

Enter the height


Area of a Trapezoid 52 meters,76 and 85 is 5440.0 meters2

Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 52 meters,base2 76 and 85 is 5440.0 meters2


    Area of Trapezoid 52 m by 76 m by 85 m in other units

Value unit
5.44 km2
3.3802677 mi2
5440.0 m2
17847.7690289 ft2
214173.2283465 in2
5949.256343 yd2
544000.0 cm2
5440000.0 mm2

Steps:

Given that base1 = 52 m and base2 = 76 m and height =85 m

Substitute the values of the bases(b1 = 52 m and b2 = 76 m) and height h = 85 85 into the formula for the area of a trapezoid.

Area = $1\above 1pt2$ * height * (base1 +base2)

Put the value of base and height value in Area Formula.

Area = $1\above 1pt2$ * (85 m) * (52 + 76) m

Add the bases value b1 = 52 m and b2 = 76 m

Area = $1\above 1pt2$ * 85 m * (128.0 m)

Multiply 85 m and 128.0 m

Area = $1\above 1pt2$ * 10880.0 m2

Divide 10880.0 m by 2

Area = 5440.0 m2

∴ Area of a Trapezoid 52 m by 76 m by 85 m is 5440.0 m2