Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (base 1)

Enter the Base (base 2)

Enter the height


Area of a Trapezoid 45 centimeters,79 and 31 is 1922.0 centimeters2

Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 45 centimeters,base2 79 and 31 is 1922.0 centimeters2


    Area of Trapezoid 45 cm by 79 cm by 31 cm in other units

Value unit
0.01922 km2
0.0119428 mi2
19.22 m2
63.0577428 ft2
756.6929134 in2
21.0192476 yd2
1922.0 cm2
19220.0 mm2

Steps:

Given that base1 = 45 cm and base2 = 79 cm and height =31 cm

Substitute the values of the bases(b1 = 45 cm and b2 = 79 cm) and height h = 31 31 into the formula for the area of a trapezoid.

Area = $1\above 1pt2$ * height * (base1 +base2)

Put the value of base and height value in Area Formula.

Area = $1\above 1pt2$ * (31 cm) * (45 + 79) cm

Add the bases value b1 = 45 cm and b2 = 79 cm

Area = $1\above 1pt2$ * 31 cm * (124.0 cm)

Multiply 31 cm and 124.0 cm

Area = $1\above 1pt2$ * 3844.0 cm2

Divide 3844.0 cm by 2

Area = 1922.0 cm2

∴ Area of a Trapezoid 45 cm by 79 cm by 31 cm is 1922.0 cm2