Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (base 1)

Enter the Base (base 2)

Enter the height


Area of a Trapezoid 22 meters,55 and 69 is 2656.5 meters2

Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 22 meters,base2 55 and 69 is 2656.5 meters2


    Area of Trapezoid 22 m by 55 m by 69 m in other units

Value unit
2.6565 km2
1.6506767 mi2
2656.5 m2
8715.5511811 ft2
104586.6141732 in2
2905.183727 yd2
265650.0 cm2
2656500.0 mm2

Steps:

Given that base1 = 22 m and base2 = 55 m and height =69 m

Substitute the values of the bases(b1 = 22 m and b2 = 55 m) and height h = 69 69 into the formula for the area of a trapezoid.

Area = $1\above 1pt2$ * height * (base1 +base2)

Put the value of base and height value in Area Formula.

Area = $1\above 1pt2$ * (69 m) * (22 + 55) m

Add the bases value b1 = 22 m and b2 = 55 m

Area = $1\above 1pt2$ * 69 m * (77.0 m)

Multiply 69 m and 77.0 m

Area = $1\above 1pt2$ * 5313.0 m2

Divide 5313.0 m by 2

Area = 2656.5 m2

∴ Area of a Trapezoid 22 m by 55 m by 69 m is 2656.5 m2