Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (base 1)

Enter the Base (base 2)

Enter the height


Area of a Trapezoid 19 foot,93 and 83 is 4648.0 foot2

Area of a Trapezoid is equal to 1/2 times the height times the sum of the bases(b1 + b2). If a Trapezoid has a base1 19 foot,base2 93 and 83 is 4648.0 foot2


    Area of Trapezoid 19 ft by 93 ft by 83 ft in other units

Value unit
1.4167104 km2
0.8803052 mi2
1416.7104 m2
4648.0 ft2
55776.0 in2
1549.3333333 yd2
141671.04 cm2
1416710.4 mm2

Steps:

Given that base1 = 19 ft and base2 = 93 ft and height =83 ft

Substitute the values of the bases(b1 = 19 ft and b2 = 93 ft) and height h = 83 83 into the formula for the area of a trapezoid.

Area = $1\above 1pt2$ * height * (base1 +base2)

Put the value of base and height value in Area Formula.

Area = $1\above 1pt2$ * (83 ft) * (19 + 93) ft

Add the bases value b1 = 19 ft and b2 = 93 ft

Area = $1\above 1pt2$ * 83 ft * (112.0 ft)

Multiply 83 ft and 112.0 ft

Area = $1\above 1pt2$ * 9296.0 ft2

Divide 9296.0 ft by 2

Area = 4648.0 ft2

∴ Area of a Trapezoid 19 ft by 93 ft by 83 ft is 4648.0 ft2