Area of an Irregular Quadrilateral Calculator
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Area of an Irregular Quadrilateral diagonal (e) = 9 in, diagonal(f) = 2 ft and radians = 1.9 is 204.4008189 in2 or 1.4194501 ft2.
Area of an Irregular Quadrilateral diagonal (e) = 9 in, diagonal(f) = 2 ft and radians = 1.9 is 204.4008189 in2 or 1.4194501 ft2.
Area of an Irregular Quadrilateral diagonal (e) = 9 in, diagonal(f) = 2 ft and radians = 1.9 in other units
Value | unit |
---|---|
0.0051918 | km² |
0.003226 | mi² |
5.1917808 | m² |
17.0334016 | ft² |
204.4008189 | in² |
5.6778005 | yd² |
519.17808 | cm² |
5191.7808001 | mm² |
Steps:
Given that Irregular Quadrilateral diagonal (e) = 9 in, diagonal(f) = 2 ft and radians = 1.9
We know that, Area = e * f * sin(α)
Put the values of e, f and α in above Area Formula
Unit Conversion of Width 2 ft = 24.0 in
2 Foot is 24.0 inches
To convert Foot to Inches
we know that, 1 Foot = 12 inches
To convert Foot to inches, multiply the foot value by 12.
Result in Foot: 2 ft × 12 × in/ft
Cancel The Comman factor of ft
Result in Inches: (2 x 12 in)
Multiply 2 into 12
Result in Inches: 24.0 inches
∴ 2 Foot = 24.0 inches
A = 9 * 24.0 * sin(1.9)
Simplify the above equation
A = 204.4008189 in²
∴ Area of an Irregular Quadrilateral diagonal (e) = 9 in, diagonal(f) = 2 ft and radians = 1.9 is 204.4008189 in²
or
Unit Conversion of Length 9 in = 0.75 ft
9 Inches is 0.75 feet
To convert Inches to Feet
we know that, 1 Inches = 0.0833333 Feet or
1 Foot = 1/12 foot
To convert Inches to Feet, divide the inche value by 12.
Result in Foot: 9 × in/12 × ft/in
Cancel The Comman factor of in
Result in Feet: $9\above 1pt12$
Divide the 9 by 12
Result in Feet: 0.75 feet
∴ 9 Inches = 0.75 feet
A = 0.75 ft * 2 ft * sin(1.9)
Simplify the above equation
Area = 1.4194501 ft²
∴ Area of an Irregular Quadrilateral diagonal (e) = 9 in, diagonal (f) = 2 ft and radians = 1.9 is 1.4194501 in²